TRANSCRIPTIon

Jonah: Welcome to the Showcase Webinar Series. Today’s Webinar is titled Load Distribution: Trolley Beams and 2-Crane Picks. This webinar is going to be great. We have 3 workshops that, I know I didn’t say this in the beginning, but they’re going to make you think a little bit. I hope everybody is okay with that. You should have received an e-mail from me a little bit earlier today of a workbook that will help you follow along and maximize your learning in this period. If you didn’t get the e-mail, that’s okay - there’s still time. You can go to ITI.com/showcase-webinar-materials and the url is on the screen there. All you have to do is go to this site, click that link, and you’ll have PDF to help you follow along.

So just before we get started, I only have a couple of items I want to touch on, so let’s get to it. At ITI, it is our duty to be regarded as the world’s foremost provider of educational and technical services for those who use cranes, rigging and load handling equipment. We try our best to accomplish this at a daily basis through training courses at both client locations and our three American training centers. One of our core values is innovation. We take great pride in finding solutions to all of the challenges brought to us by ever single client. That’s something we do through our training centers, our courses, the consulting - something that is a part of our day to day activities. Another way we try to fulfill our mission is by providing a number of crane and rigging resources to all who are in need. When you have some time, and I have to emphasize that because you can spend hours in here, we’ve put the url up here: iti.com/crane-rigging-resources here you can have access to things like ASME interpretations, there’s three different blogs, info kits, whitepapers, ebooks, a pretty cool collection of rigging videos and so much more. Like I said, you can get lost in there for hours. One other thing, if you think of something that can be of use to you or that’s valuable to you, but not on our resources page, please let me directly know. As mentioned earlier, we can get a solution for you.

I want to mention two new exciting developments at ITI, before I turn things to Mike, so in January of 2015, a brand new programs - Fundamentals of Rigging Engineering is expected to launch. We really do have a dream team, I know that’s an over-used term, it is true in this case. A dream team of developers and instructors who are putting the final touches on this program as we speak. What’s different and really innovative about this, and one of the greatest benefits about the program, has a unique format. So most practice students are going to be working full-time, and possible - to complete this program entirely in an online, on-demand format. There are hands-on options as well for those who want to go that route. However, it’s really just a great program. As you can see there, we have a few examples of screen shots of what the program is going to be at MIT. It’s going to be lecture recordings from those 14 dream team industry experts. What’s unique about this, you’ll have a stream of lectures, as well as notations that they make on their screen. So it’s a pretty different learning format - not just a PowerPoint slide with someone talking and you’re not interacting with them. It’s great.

In addition to the lecture recordings, students are gong to participate in discussions, there will be assignments related to each module. participants will be able to work in specific workshops with every learning objective and finally, exams. So for more information on the course, and you can download the key book that is a little more in-depth on each specific module, just visit: riggingengineering.com One more thing, it probably won’t apply to everyone on the line, but coming up in less than 2 months is the advanced crane and rigging training event Edmonton. So this is a 2 and a half day event that is going to feature 4 developers of the fundamentals of rigging and engineering as instructors. Besides the obvious of a great source of crane and rigging and heavy transport information, attending the workshop is a great way to discover potential gaps in the organization’s current lifting and hoisting operations. You can get more information on the workshop at ITI.com/edmonton Our host today is Mike Parnell, most of you know him, and I’m sure most of you on the line are somewhat familiar with his work in the crane and rigging industry. I do want to point out that Mike volunteers most of his time in the industry by serving as the Vice Chair in the ASME B30 committee, and as the chair of the ASME P30 Main Committee. On that note, I want to mention, Mike will be taking part in a live workshop on the recently released P30.1 standard and that is taking place in less than a month, May 22nd in Baltimore Maryland. So if you’d like more information on that, you can e-mail me directly at jonah@iti.com. Or you can visit ASME.org for more information.

Sorry for the overload of information there, it’s time for the main course today. I’m going to pass control of the screen today and have him take it away. One final note, if you guys have questions at any point today, please enter them into the questions pane and I’ll be taking them as they come in, and give as many of them as I can to Mike at the end of the presentation. Let me get the screen over to Mike. Whenever you’re ready, Mike.

Mike: Okay, Jonah. Do I have the title screen up here?

Jonah: Yes, Sir. You’ve got the title screen there.

Mike: Okay. Fantastics. Thank you, Jonah. Thank you very much earlier, everybody joining me. We really spend, it’s a crazy week - our prayers and thoughts toward folks down in Tornado Valley, I used to live there and still visit on a regular basis. Hope the storms get dissipated and go away, we’re hoping that folks and families are recollecting. A lot of volunteers are helping out and getting everybody back on their feet. We’d like to welcome everybody here. We’ve got as a general rule, we’ve had in the neighborhood somewhere along 15 countries that are participating - I see African Minerals here, Central Oceans, BP Alaska, we have a number of folks around North America, and probably 25-30 states represented, in the visitors group today. CB & I, Access Constructions, we appreciate everybody participating, JB Drivers, Nest Crane, Nest and Camble, Crane Center, Army Corp of Engineers, we have a lot of folks sitting with us today, ready to go forward. This particular workshop, if you don’t have a calculator with you, might want to pull out a smart phone with a calculator on it. People kid me - I kind of pull out an old phone once in a while and I try to upgrade a little bit. This particular workshop involves math, but we got some helpful formulas to help us get through that. From the screen I put up panel 2 from our Journeyman Rigger’s Reference Card - This panel, we’re going to be focused on the second and third formula series, to help us figure out the second one is - if you’ll notice, I’ll draw a line here- the second one is about knowing where the center of gravity, but we don’t know how much load it is going to put to our cranes or hoist or lifting system. At the top of each inner lift boxes, inside the formula, we’re going to look at share Load A and share Load of B and that can help us understand anticipate the loading to those cranes and systems. The last right below it, if we’re using an MRI or crane scaler dynamometer and we maybe do a test pickup to the other end, and what’s that going to help us resolve is understand the center of gravity from A or from B.

So, this particular panel, in the length of the PDF Jonah made available to everybody. This is going to be very important to have in front of us and these formulas that we have, they’re boiled down to non-engineer status. It is the engineer’s way to attack a problem this with the sum of moments type formula approach. We broke that down to, where all of us can wrap our arms around and get to the same end goal, same destination. But at a level simpler format, how we’re might want to approach our work. Let’s use this formula series and tackle our first assignment here. Up on the screen, take a look at - I’m going to wipe this out for a second - this right hand image is the load trolleyed from left to right, so our actual position 1, is on the left and that’s the initial liftoff. We have the initial trolley beam that’s supported by building structure that’s been permitted by the in-house engineer. It has a total span of just for reference information, a span of 15 feet, and we can trolley - hoist this up, and trolley, set the load down onto a rolling cart. Rolling cart has something of an obstruction here, pick it up, horse, trolley, and set down. So that’s our assignment. We want to know: what is the resulting load on those 2 overhead support. West of the support beam and the East support Beam. Right out the get go, we refer back to our formula, let’s mark what we do know about this in the initial elements. Bounce this screen up a little bit, and bring in this view. Getting rid of some of the notations so we can quickly get a clear picture. What I’d like to do is ask you to write in some information we know. We’re looking for the share of load at A, call it left Side A and right side, east support, B. Let’s note that, A on the left and B right. So on the initial lift, represented by 4200 pounds, includes the weight of the load, the rigging and the chain hoist and trolley. That’s in the information block on the right of the suspended weight. So we’re going to lift R1 - R1 is about 2 ft mark and from there, we’re going to figure out how far it is to our east support beam. In this case, it is 13 ft total, 8 and 5, and that’s going to run 2. So let’s mark, A is on the left, run 1 is with that at 2 ft, B is on the right, run 2 is on let’s use our formula. Certain information we have, right here on panel 2 - what I’m going to ask you to do is, and I’m going to do the same thing, let’s record that information to another sheet of paper, and we’re going to fill in the blanks here. we’d like to know share of load, using first set of information blocks here, legend out to the right showing what those numbers and variables represent. Let me prop a sheet to the screen here. I’m going to first highlight, I’m going to ask you to do the same thing with me, Share of Load at A draw a line down there, Share of Load at B, and write down formulas here ,leave some space in between - asking you to do the same - R1 +R2 = Total Span, drop down leave some space. R2 Run 2 Divided by Total Span equals percentage. Apply that percentage times total weight equals share of load at A. Alright?

Then, let’s also write our formula in on the right side, so the first line is the same. R1 + R2 = Total Span, in this case, we’re going to use R1/TS is percentage. then percentage times weight equals share of load at B. Excellent -now fill in the information we know. Remember back on our drawing, that we have R1 as 2 ft, R2 is 13 ft, W is 4200 pounds. Let’s put that into the formula set. R1 is 2 ft plus 13 ft equals a span of 15 feet. We’re going to use that R2, which is13 divided by 15, equals a percentage. Punch that up and see what we get. If we just keep rounding to 2 decimal places, that’s great. If we get something that ends in 5 we’ll then probably use 3. But let’s just stick with 2 right now. I get  87 percent, divided by 15. So we’re going to take 87 percent down to the next line times a total weight of 4200 pounds. That’s going to get Share of Load at A is 3654, Okay? That’s in pounds. I’m going to write that over to our answer page. Let’s work on right side formula now. Please work your pages going through. Given you all the documents, so there’s full interaction here. 2 and 13 equals 15 again, here on the east side, the long ways away from the load, it’s going to be smaller value, smaller payload weight to get that East side support beam. So that is why we got 2 ft divided by 15 ft, giving us 13 percent. 13 percent of that total weight, it’s going to be an easy habit to get into, our value there is 5. I’ve got 546 pounds. Let’s take these values to our page there real quick and let’s put those up on the screen as we get a fill in the blank there. So I got portion of load less being, which is A, led portion of 1, and we got 3654.

Next one down, we get load at east beam for position 1 is 546. Something we want to do real quick is 3654 plus 546 is, as a double check, is we did get back to our 4200 pounds. That’s a good double check. Another thing you want to do - it’s easy to get inverses working with R1 and R2 in those positions, this is something we teach a lot, the load short distance of these 2 is the 2 ft versus the 12 and that would be result in a stout weight. The long distance should result in a light weight. So then the acronym, SS - Short Stout, LL- Long Light, did I get my numbers in the right place? You think about the pick point closest to the CG should be carrying more weight. That is the idea. This pick point is closest to the weight and is definitely should be the lion share of the load there. This case is 3600 pounds plus 3654, so we are 546 on the other side. We do have our numbers in the right place. Okay, excellent. What we want to do then, let me get rid of these variables and let’s get a clean slate.

What we are going to do right now, just going to cover these guys up for a minute because we already hoisted the load and we know what those values are. So now we’re trolleying it down to the cart, the load card, and the total - what we want to do now is identify - what’ si our total R1 and R2. So that’s the initial 2, eight, so this is going to be 10 ft. Our balance to the east side is 5 ft. So right off the bat, some things should be coming up naturally to us. If you just take a look at 10 plus 5 equals 15. Our distance actually hasn’t changed, but we’re going to do our formula here just a second. If you just put that 15 under each one of those distances, we have 2/3rd plus 1/3rd or the total distance. so our distribution of weight should be a 1/3rd, two thirds split. We should really have the center of gravity, the pick closest to the CG carries more load. So really, at the end of the day, we should anticipating two thirds of the weight to be on the east side. One third of that weight to be on the west side. So we want to start building a pattern in our minds. How are we getting these numbers and how are they coming together. Let’s go back to our formula and go into the values and formula we have. Leave this primary formula on the screen then fill in the new values for the new set on the trolley system. So on this one, Run 1 we identified is 10 ft, Run 2 is 5 ft, so what is our value then, on our total span, 15. This time we’re going to take Run 2, which is 5, divided by total span of 15, that’s going to give us the percentage, .33. Apply that percentage down to 4200, what is .33 times 4200, I got 1386 pounds. Alright. Let’s fill in the information to the right on the Share of Load to the B side and fill out the initial information there. First is 15 ft, then we’re going to use this part 1, so that’s going to be 10 divided by 15 ft and that is going to be 67 percent. Let’s apply to that last line, .67 times the weight of 4200, punch that in the calculators, 67 percent of 4200 - and I hope we did that correctly - down to 2814. So we’re going to take those values, go over to the main page, scroll up just a bit, should be able to roll those values into position west beam loading position to, we should have 1386 and position on the east beam, we should have 2814. Remember the question we asked a minute ago, add these 2 up and see if we go back to 4200. So I’ve got 0, another zero, carry the one I got 2 and carry 2I got 4. so we have 4200, as our target point there. That makes sense. And, we want to continue asking ourselves the question, is the light weight, does that make sense on this side, 1386 and does that 2814 make sense over here, for our end result. We got 1386 on the left side, 28 and change on the right side, and so, our center of gravity closest to that east side will be further away from the west side at A. So we got more load on B, less load on A, and that makes sense too - Short Stout, Long Light - so they switched positions from the first example.

So the idea there is to get our heads around what will transition/happen when we move loads across. We suspend the charley beam, we have a couple of hoist, with a couple of transportable trolley charley beam put a stop sign, so the trolley can only go so far. Although it will roll off a load, and these charley’s are suspended by dynamometers up to a support system. You can actually see the values change on the dynamometers as we move that load from left to right. It might start off out here, relatively speaking - at zero, and then as we charley across, we might stop here at 600 versus 400. As we continue to charley across, we might end up over here at 200 on the back side and 800 on the leave side. Actually, see the values change up at the dynamometer as we make the transition. It’s a very good learning exercises, we use it all the time at our Master’s Rigger and Journeyman workshops, learning and numbers tell the tale - it always makes a lot more sense when you see it. A little more, it locks it in there, of course, so we get a better confidence when we’re starting to run numbers and do estimations without having need of electronics for some of those lifting devices. Alright, excellent.

Let’s take a look at the next one. By the way, Jonah will be putting an answer key, available after we’re done here. So if you don’t pick up, we’re using along, don’t worry - we’ll have an answer key ready for you with all this detailed calculations as we go forward. Here’s the idea - the next problem we have 2 double hook picks on the same bridge. It’s on the bridge crane, right up above there, we have a 30 ton hook and a 5 ton hook. We got a big brother and little brother on the same bridge. The idea is, we’re picking up this large shaft with two gears on it. We want ot move it, transit it, and eventually land it. So before we get going, we want to make sure we have each hoist necessary to make it load move. Since we’ve got two different hoist values, we want to make sure we’re loading to the right end. What we need, for some reason, overload this or that, we might have to - instead of rigging to that gear- we might have to to rig further out or further in based on the center of gravity. or on this particular case, on the 5 ton to close end of the CG. Do we need to fill it out. What do we need to do to fill up to the rated capacity and those hoist systems. So knowing what we’re picking up is really important. You want to know, you shouldn’t be lifting or handling anything that we don’t know the intended weight or tension that’s going to be applied to that hoisting system or load handling equipment. And we’re rigging to make sure we’re staying within its rated capacity.

Let’s do this - take a look and identify three significant pieces, we’re going to challenge ourselves to tackle this in two steps, two stages. We’re not going to need the whole 1 time, so let’s deal with 2 items at a time here. Notice to the left we’ve got a shaft at 2000 pounds and that small gear, or little gear, is 5000 pounds. So what I’ll do is find the combined center of gravity for each one of those two pieces. Once doing that, we’ll then come back and find the CG of those two combined with the big gear. So the big gear is our last step, we won’t worry about it right now. We’ll just work on those two first components. So, let’s take a look at this shaft. It’s uniform in its length. There is a hole in it, there’s not a complete solid. There is a hole there, but it’s at 10000 pounds and the overall length of that shaft is 30 ft. So at 15 ft, we’re going to put a little mark, not to scale drawing, but we’re going to put a mark somewhere about where we think the center of gravity is for that shaft. About the midspan at the 15 ft mark. Move that over just a little bit. Then we’re going to put a CG, or bullet mark, where we think the center of gravity is for the shaft or the little gear, the small gear. So there is really no between weight, we got one at 10,000 and 5000. We’re just going to mark here on the page for a second. If this is 15 ft from the end of the shaft to the approximate CG, the center portion, it’s another 15 ft. So we’re 15 and 15, dead center for that shaft. This guy is 4 ft from the end. Notice that little 4 down there. So we’re 4 ft. So working from the right end to the middle, we want to know what this total span is. That’s an important number to us. In fact, if you just take 15 minus 4, the right hand side, 15 ft length minus 4 ft from the end of the shaft to the small gear and I’ve got an 11 ft span there, that’s an important piece of information. Let me clean this picture for a second. So if you think about a ball and box out here, I’ve got a weight - shaft is 10k, small weight over here, that little guys is 5000, what I want to know from those two are: 11 ft, where is the combine center of gravity for those two pieces? That’s the key, the goal for what we’re trying to arrive at. If you remember from our last workshop, what do we already know? Now, instead of runs or distances, we tackle in weight. So we’ve got, in effect, we’ve got a 10k pound weight and 5k pound weight and those two combined at the moment would equal 15k pounds. Do you remember, from our last exercise, if we just take the total and divide it by, all parts divided by the hole, what we discovered was - we got a two thirds, one third load split. Two third of the load one place, one third of the load weight another place. So we’re just trying to figure out, how do we apply that? The short of it is, we’re just going to apply that to 11 ft. Somewhere along there is just a large bar bell, we’re going to put two weight, one big weight at one end of the bar belt and just smaller on the other end of the bar belt. Where we pick it up to balance it? Is that perfect balance on which the entire combined weight is centered or concentrated? So, that’s what we’re going to do here.

We’re going to pull up a new page. If you would - let me get this pulled down for a minute. If you’ll notice, going back on panel 7 or 8 there, and we’re going to pull up this other formula. This is the one that I got highlighted in green. It’s known weight. I do know the weight on the left, know the weight on the right, what I don’t know is: where is center of gravity from A, where is center of gravity from B? So we’re working from the formula set on the bottom here, CG and A, CG from B, and we can get some legend information. So let’s keep that page up there for us, that’s page 8 of our handout. We want to keep that active because this is a formula that we’ll be using for this next series right here. Let’s take a look then, we’ll put this up. Get back to challenge page here, get rid of some of the information - gets cumbersome sometimes. Let’s put this on the screen and work through this really quick. What the formula says to do is to take weight 1 plus weight 2 equals a total of A. I’m going to leave this, and ask you to do the same thing. Weight 2/TW (total weight) equals percentage. Then percentage times span, which is 11 ft, is CG and feet from A. Draw this line down here and going to do the same thing on the other side, B side. So weight 1 plus weight 2 is the total weight. In this case, take weight 1 divided by total weight equals percentage. Then percentage times that span again is CG from B. Alright, excellent. So let’s fill in what we do know.

We’re looking at: weight 1 is the shaft itself, I’m going to put 10k for 10 thousand, and 5k for the small gear equals a total of 15 thousand. Then complete the next line, what is weight 2? Weight 2 is 5 thousand divided by total weight of 15 and that’s going to give us a percentage of .33. One third of that percent we were talking about. In this case, apply the .33 times the span and find out how far away from that center shaft point is the approximate CG. That span is 11 ft. That is going to give me a value times that .33 times 11. Hopefully, that’s going to give us 3.63 ft from A. We’re going to put on here just a hat mark. I know that this is 15 ft already from the left to the center point. Now I’m going to go over another, 3.3 ft, and this is my approximate CG for the 2 pieces. Im going to double check that by working the right side of formula, and I will always double check our work. So weight 1 is 10 thousand, weight 2 5 thousands, total 15 thousand. Weight 1 is 10, divided by total weight of 15, in this case is 67 percent. So we’re going to times that 67 percent by the span and punch that up, .67 times 11 and that should give us 7.37 ft. Alright, one thing we want to do then is double check. Let’s see, it’s 7.37 and 3.63, does that equal back up to 11 ft.? And it does. 3.63 plus 7.37 is 11 ft. So we got our homework done there.  Which end is the heavy end? The shaft is the heavy end, and the little gear is the light end. So we’re only going to be a little distance, so short stout, long light. Short stout there, Long Light on this side. So I am only 3.63 ft away from my original end, and there’s my combined CG for the 2 pieces.

So in thinking about that, I want to put a new value. What is 15 plus 3.63? Let’s work from the west end for a second and get a common point in our head here, so we should have a value of 18.63 ft from the west end. Let me get rid of some information here and come back in. Just going to use some of my same formula here in a minute. Get rid of this stuff. You got more paper than I do, so go ahead and clear yourself some space. So we’ve got 18.63 ft from that end to the approximate center of gravity from the two pieces. What we haven’t dealt with yet is the big gear. The big gear, where is it in the 18.63 ft? That big gear is right there at 6 ft, at the center of that gear. What we want to do then, take the 18.63 ft, track that 6 ft from the west end, and I’m going to get 12.63 as the span. That’s my new span I want to record, that’s the distance in red from the big gear to the small gear, combined CG. 12.63 is that. Alright, 12.63 is a very important piece of information we want to get right there. So, what do we know about the weight of the big gear? everybody see that? It looks like the big gear right there is 15 thousand. What do we know about the weight of the shaft and little gear? We have those two up at 15 thousand. So we got 15 thousands here, 15 thousands pounds there, and we got a span of 12.63. So let’s put that in our formula set, we’re using formula on page 8, it’s the weight 1 weight 2 formula. Let’s put in what we do know. Weight one is the big gear, so that’s 15000, weight 2 is the shaft and small gear combined. That’s 15 thousand. So we’re up to a total of 32 thousand pounds. Which is correct. That’s all parts combined. That should be easy, piece of cake, so we’ll take 15 thousand divided by 30 should give us 50 percent of the load. 50 percent, let me get rid of the bottom part right here, out of our way, and we’ve got 50 percent, the percentage is 12.63 equals, that distance 6.315 - the reason I’ve gotten it down is it ends in five, zero and we want to go ahead and use that value for just a minute. Go ahead and complete the other side, which should be identical. Also, what’s 15 equals B. It’s a 50/50 load split. So W once 13 divided by 3 equals .50, 50 percent of the same span, 12.63 should get us to 6.315 ft. Question is, did those two values add back up to 12.63, yes they do. What we’ll do then, we’re going to put a hack mark right in between the run or distance there, and I get 6.315 on each side of that. I’m just going to draw that center of gravity bullet right there. So total combined CG all three pieces together is at that point. Let’s make a mark, note on our drawing - if this is 6 ft from the end to the center of that shaft, that’s another 6.315, so we add those two together, we get a total distance of 12.32 ft rounded. 12.32 ft from the end of the round west end to the CG, that’s a real hard number - keep it in our heads here. 12.32 ft, from the west end to the CG, that’s our bullet point.

Alright, excellent. That’s important to know because we’ve got to figure out how much load we’re putting on each crane. So now, we know that we are then, in this case, let me answer the question down below here - we know that the center of gravity is 12.32 ft from the west end. This just answered my first question. The next questions are, how much load is on the 30 ft ton hook, how much load is on the 5 ton hook. That’s the whole reason we’re monkeying through this, I know it takes a lot of time, but just think about this. We don’t want to overload that 5 ton hook and pull the whole thing down. So we want to make sure we can lift and test them out, and handle it. Here’s the idea, take a look at - what do we know right now? We know the capacity of the crane, and we know the distances from the pick point, which is the center of the big gear, that’s a pick point straddling the mid gear and we know that w’re going to be picking from the center of that small gear right there. This distance, we do know is 6.32 ft, from there to there. We know that value. What we don’t know is, what is the distance from the CG to the small gear which is the 5 ton hook where it’s picking? Also available to us is that value down there below. 20 ft span close to hook. So let’s do this - let’s take 20 ft. span, minus our known 6.32, and the balance distance is 13.68 ft there. Alright, excellent. We just discovered our distances. Great. So just for curiosity, which one is going to carry more load? 30 ton or the 5 ton. Okay, getting a little more feedback here. 30 ton is going to carry more load. The center of gravity is closer to that 30 ton hook and further away from that 5 ton hook. We’re going to find out ,really quickly, what the payload of that 30 thousand pounds against those hoists. So let’s take these 2 numbers, 6.32, 13.68, and let’s go over to our run 1 and run 2. If you remember, we just use this initially, run 1 run 2, Share of Load of A, Share of Load of B. A lot of rigging decisions can actually come right from these 2 formulas from our card. We’re going to focus on discovering what those load values are to those hoists or crane. It’s the center formula we’re using. We’ll put this up on the screen here, get back to the formula preset for us. What’s the share of A, which is the 30 ton, which is the share of load of B, which is the 5 ton. I’ll make a note up here of which we’re talking about. Share of Load at A, 30 ton, Share of Load at B, 5 ton - filling out what we know, carrying it from what we’ve already drawn, 6.32 is run 1, and 13.68 is run 2. Those two add up to be 20 ft. Excellent. Alright, we’ll do what we’ve already know a minute ago - take that 15.68 divided by total span of 20 ft, it gives us about 68% for percentage. Now what do we do.  Let’s take that 68 percent and keep going down the formula, percent times 30000 pounds equals, a resulting load of 20,400 pounds. Excellent, perfect. Give you a few minutes, take a look. Get the weight on the 5 ton crane. I’ll slowly put this up, and put the data in there. We know 6.32 for run1 and 13.68 for run 2 is 20 ft. Take it down, 13.68 divided by 20 ft span, that’s going to give us a percentage of .32. We’re going to carry that down - what is 32 percent of 30000? Take that value, and it is 9600 pounds. excellent. Alright. Good thing for us, because we’re on a 30 ton crane, we got 20,400 30 tons is 60,000 so we’re in great shape there. we’ve got 20,000 pounds to load and change on a 60000 hoist chain hook. On the other side, we’ve got a 5 ton hook, 10000 pounds, and I’m only imposing 9600 pounds. That’s a pretty high lift, isn’t it? It should still be within the capacity, should be in good shape - cranes inspected and it’s all healthy, and everything is good with it.

So let’s take a look - we’re going to transfer information over. Pull this up so we can see this. I just discovered that we’re going to be able to put 20,400 on the 30 ton hook and we’re going to put 9600 on that 5 ton hook. Excellent. So we are within the rated capacity. Okay, super. Alright, the next item, phew - that’s a lot of work. Guys doing great here. Next question, here’s the process and procedure - this is where we get into a bite sometimes - that, well, what’s the job? Now that we know, let’s just say that, put that CG - not perfectly to scale, but just to get the idea - put that center of gravity right in here somewhere. So we know we’re about 6 and 1/3rd feet from 30 ton hook and over 13 and half feet from the 5 ton hook. We know where we’re at. What we got to do is, put this shaft in double gear set onto some spans. So we can do some repair work on the ears. These two stands, we’ve got a little picture - illustration provided for scepter on the upper left - and this stand looks sort of a fall horse that’s been custom built to accept this shaft at both ends. We’re just about to lower the shaft and double gear to those two stands. Now, take a second to think about this - we’re about to lower this down - this shaft is going to come up to this saddle from the west side, or into this saddle on the east. It’s going to cradle on the saddle. The question is- which side do we lower it first? The first place, they run at different speeds, different parts of line, different capacity, different drum sizes - everything runs different. So, which end should land first? That’s sort of the first question. Should we land the west end first, or the east first? Take a look at it, it can cost us big time if we don’t get our procedure down right. That’s the bigger part of why we’re doing this workshop. So take a look at it for a second from the left and the right side. While we’re doing that, turn page here and get some numbers up. Okay. So that’s our effort here. Question is: I want you think about this, we could have been, in some combination, and I want you to think about this. One we can have a 30 ton crane, and that far east stand supporting the shaft if we lower the right or the east end first. The other decision can be, the other one is we can decide let’s have a 5 ton crane hold up and we’re going to lower the 30 ton and let that end sit on the shaft. That’s the whole idea. Something should jump out at us, that should be very quickly apparent. Take a look. In the first case, I’m going to put a thin line down here, if we land the east end first, look how close the 30 ton is and how far that east end saddle is. That’s a nice proportion - what we’re doing is we’re resting that further away. Our pick point basically changes from this line to this line and it’s going to add a little weight to the 30 ton crane but we can probably survive it because we got 60 ton in capacity. To do it otherwise, let me back these out for a second, let’s do this - use the yellow here - look how close we are to that five ton hoist to the CG and how we are with that west end saddle, west end shaft stand. In this case, we’re not perfectly 50/50, but be darn close. If we remember something, the total is about 30 thousand pounds, we’re almost 50/50. We’re running to see somewhere well above 10 thousand pounds on that 5 ton hoist if we decide to lower the west end first. That’s the whole deal. We have a great opportunity to upload the 5 ton hook. That’s the main element I want us to walk away with. When we’re picking in two places, here’s the deal. We’re picking in two places, we’re going to pick here and here, but we’re going to land in two other places. Out there and out here. Being really careful, even a mobile crane, overhead crane, or crawler crane or something else - you can get in a big bind in a hurry by picking those two points and landing two other points based on what the integrity and capacity of those two hoisting systems are. It’s a real procedural decision and we got to hammer that down. I’m going to expedite this for us just a little bit.

Let’s take this on the next page on the powerpoint you have a whole gob of numbers. I don’t want to burn up a lot of time right now but I know you can get to these values. I’m going to run this down for us real quick, so that we can get our - put a CG bullet in here. If we contact the east saddle, we’re going to do this first - do the 30 ton hook in the east saddle with that combination. I”m going to put the values up there. I know you can add up all those numbers and do all the formula, of what I’ve just done. But we do this first. What we started at, our initial numbers on east hook were 20,400. Based on the new distance out from that 5 ton hook to east saddle, that’s going to go up to 21900, what will happen at the east saddle is 8100. So these saddle, when we land it, when it comes down, the 5 ton hook lands on the east saddle, the bearing weight is 8100. There is some argument. What we did was we went to the outside of that saddle edge to get the worst case scenario. just so you notice, it would hit the outside edge first, and once it saddles up, it’ll be in the center, more or less, whip. So we’re just taking the worst case. We got 21900 and 8100, those add back up to  30000 pounds. First is, 5 ton hook lowers into the saddle. Second step is to put that 30 ton hook, lower it down, and put that in the west end saddle. Those 2 values result in 21900 and 8100 on the eastern set down, eventually pay off to the west end load hook and it’ll set down to that west saddle. Now let’s consider the alternative. Considering bringing this west end down first, what happens there. Initially, we have 20400 and 9600 for suspended weight, in this case, the load out here will be 16,500. You guys can do the run 1 run 2, all come up with this information since we’ve been through those formulas. You know what those runs are, this might be A and B, and run 1 and run 2 will be those spans or distances to the center gravity and so on. We already know all that stuff, we’ve already done it. Now we’re going to discover, that 9600, which is the kicker, 16500 on one end, and what’s going to happen is, it’s going to grow 30500 pounds. We are in an absolute big overload. We’ve got to be really careful, we’re now at 35% past the 5 ton hook capacity. By lowering the west side first, and eventually lowering the east side. The one that we always want to make sure we’re double checking our values. Let me go ahead and put these numbers on the next page.

Let’s record these and these are the values - I know that guys can do the math, and gals can do these, I’m going to put 21900 and 8100 for the first case. Second case, we’re going to put 16500 and 13500 and back up to 35000. This is an overload for the 5 ton crane. 5 ton hoist. So we just discovered, we can get the weight, the center of gravity no problem. We can make sure we’re within rated capacity. Now we’re about to set these down on some forks and oh my goodness, we’re going to be overloading one crane if we don’t do it  right, step by step procedure. That’s the big procedure here. There is an answer key for this, of course. That’s available to you once we conclude the webinar. Just about finished. Want to throw something back to you. A fun, Mike’s rigging set mystery we’ve used over the years. We created two brothers, Stinker and Tinker, and if you’ll notice - this whole plays out to the real world - they’ve got deer meat sitting on a 25 pound pole tied up at the center. The question is, when they started carrying all this, this is the same thing as the weight distribution and load crane and two cranes. But we got two people here. The deer meat secured at the 25 pound pole at the center. They started carrying it and they were three feet from the securement point. That resulted in 75 pounds a piece, 75 pounds there, 75 here. Over time, Tinker gets tired and gets to slide back down on the pole, now he’s at 5 ft distance instead of 3 ft distance. Does that change the weight to each brother? Absolutely. You can tell the direction they’re heading, Tinker must be having a pretty good jolly laugh over the whole thing. So, it gets back down to: what simple? I’m at 3 ft. and I got 5 ft and the total span is 8 ft, just divide all parts by the whole, 8 8 and 8, we’ve got 3 eights on one end and 5 eights on the other. You remember that inverse, that transition, so we’ve got 5 eights on Tinker, 3 eighths of the load on Tinker and further away he gets from that meat, the less he’s carrying pick point closest to the CG carries more load. That means Stinker is carrying more load. In pounds, that’s going to result in about 94 pounds and 56 pounds. So those brothers are going to have a discussion and a tumble in that. Stinker’s gained in weight all of the time and Tinker’s moving away from it. So moving a little bit of a fun deal. So 110 workshops in Mike’s rigging set mysteries and it’ll be great if you want to pick up some workshops that are problem solving. They’ve all got answer keys with them. The bookstore’s got them. We use a lot of them, also, in our master rigger’s card. We’ve got 10 lower workshops that are rigging in the outdoors where these guys show up and present these fun, home-grown backyard rigging activities that give us a pause for thought. Okay, very good. Jonah, do we have all the answers? Any questions by anybody that have been coming in during the webinar or are we in pretty good shape?

Jonah: You’re pretty clear right now. Either we’ve got some pretty shy people out there or they’re following up well in the workbook. I don’t have anything right now. If something does come up, please send us an e-mail. Even though after this is gone, the recording will be posted in 24 hours. I can relay from somebody that can pick up at a later date.

Mike: I want to say thanks to everybody. I want to really reinforce the idea, there are three axioms of rigging and that is load weight, CG, and Rigging Method. Those are the three basic starters for anything we want to do in rigging. What is the weight? We got to do weight estimation using techniques, come up with the weight, whether it’s solid mass or combination of motors and pumps and electric, switch boxes, whatever the items are - what is the weight? Got to have a total weight. Second, where is the Center of Gravity? Where is the approximate CG because always that CG is going to dictate what my rigging tensions are? my rigging tensions are going to influence my rigging methods to some degree. Do basket it? do I choker hitch it? Do I direct connect it? how many cranes are going to be picking up? One crane. Well, all the rigging is going to come together one peak point. What would be going straight up and do I have some alternatives there for rigging methods? It all plays out.

So, load weight and center of gravity will always drive us to picking a rigging method that will get you to the finish line to ensure we have sufficient capacity and rating for all the rigging sling shot, come-along chain falls, all the things we are using. So those are the three things we’re using. So you got a rigging program, you need a rigging program, where do you start to emphasize that with the new folks coming along - what’s the weight, where’s the center of gravity, and what’s the rigging method we want to choose to provide stability and proper and correct capacity for the rigging included? So that concludes our day. I really appreciate everybody participating. We look forward to seeing you on the next webinar that we’ve got. We’ve got a number of activities for this summer, stay in touch and we’ll make sure you’re informed about those programs as they come up. This is Mike Parnell signing off. Thanks so much. Hopefully, we’ll see anybody who wants to come up to the big critical lift planning, the P30 ASME, P30.1 program in Baltimore on May 22nd and ASME.org has their website. You can also contact iti.com and we’ll give you the same information. Have a great week and weekend coming up, we’re looking forward to seeing you in the future. Thank you for being such a good friend to ITI and participating with us along the way. Take care and everybody have a safe day.